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Engineering Data
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Catalog excerpts

Engineering Data - 1

■ Misalignment Fundamentals ■ U.S. Inch Clearance / Interference Fit StandardsKeyway Recommendations ■ ■ Lovejoy, Inc Metric Clearance / Interference Fit StandardsIEC Motor and Nema Motor Frame ■ Standards >

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Engineering Data - 4

Parallel MisalignmentFigure 1Angular MisalignmentFigure 2Axial MisalignmentFigure 3Composite Radial Misalignment Figure 4 Life Versus Misalignment Figure 5 > The function of a coupling is to connect driving and driven equipment. In addition, a coupling serves to protect costly equipment from the effects of misalignment, shock loads, vibration and shaft end float. Of these factors, the most common is misalignment and end float (also known as axial misalignment).Misalignment is a condition created by two shafts whose axes are not in the same straight line. There are three forms of...

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Engineering Data - 5

When it is not possible to measure the misalignment of a system, or in designing a new system, the following method can be used to estimate angular, parallel and combined misalignment. Each type of misalignment is first calculated and then the results are combined.To calculate the maximum angular misalignment, the distance (L) and angle (a) must be known or estimated (see example below). First, calculate the angular misalignment noting the critical plane or midpoint of the shaft ends. Second, using the maximum parallel misalignment, be sure to consider both horizontal and vertical...

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Engineering Data - 6

One HP is the rate of work required to raise 33,000 pounds one foot inone minute. Force x FPM Torque (in pound-inches) x RPMHP = חחחח HP = חחחחחחח-- 33,000 63,025 Torque (in pound-feet) x RPMHP = חחחחחחחח 5,252 > FPM = Feet per minuteRPM = Revolutions per minute 15 HP @ 1750 RPM is: 15 x 100HP/C = חח = .85 HP per 100 RPM (HP/C) 1750Using .85 HP/C, the HP rating @ 800 RPM is:.85ח x 800 = .85 x 8 = 6.8 HP100 Nm x RPMKW = חחחח 9,550TQ = F (force) x R (radius) > When the HP is given and the RPM, N, is known, HP/C is: HP x 100HP/C = חחח NOnce HP/C is known, HP @ N RPM is found by HP=HP/C x N >...

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Engineering Data - 7

An overhung load is a bending force imposed on a shaft due to the torque transmitted by V-drives, chain drives and other power transmission devices, other than flexible couplings. Most motor and reducer manufacturers list the maximum values allowable for overhung loads. These values should be compared with the load actually imposed by the connected drive.Weights of the drive components are usually negligible. The formulas are based on the assumption that the load is applied at a point equal to one shaft diameter from the bearing face. Factor F, shown at right, depends on the type of drive...

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Engineering Data - 8

HPSpeed(RPM)Torque > m ConstantזIncreases Decreases m > m ConstantזDecreases m Increases > m m Increases ConstantזIncreases Decreases m ConstantזDecreases m > m m Increases Increases ConstantזDecreases m Decreases m Constantז > Kva To FindAlternating CurrentTo FindAlternating or DirectCurrentSIngle PhaseThree PhaseAmperes when horsepower is known HP x 746E x Eff x pf HP x 7461.73 x E x Eff x pfAmperes when voltageand resistance are known E R Amperes whenkilowatts are known KW x 1,000E x pf KW x 1,0001.73 x E x pfVoltage when resistanceand current are knownIR Amperes whenKva are known Kva x...

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