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Shock absorber - Zimmer GmbH - #14

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Brake, Damper, Clamping element, Linear brake, Braking element

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PowerStopj
PowerStop
Formulas/Calculation examples
Formula signs:
P
motor capacity
[kW]
W1
kinetic energy per stroke;only mass load
[Nm]
HM
arresting torque factor for motors 2,5
1 - 2,5
W2
energy/working of driving power per stroke
[Nm]
M
starting moment
[Nm]
W3
total energy per stroke(W1+W2)
[Nm]
J
mass moment of inertia
[kgm2]
W4
total energy per hour 8W3xn)
[Nm/h]
g
earth accleration = 9,81
[m/s2]
me
effective mass
[kg]
h
height of drop with impact damper stroke
[m]
m
braking mass to be decelerated
[kg]
s
impact damper stroke
[m]
v
velocity of impact mass
[m/s]
L7R/r
radius
[m]
impact velocity at shock absorber
[m/s]
Q
reacting force/supporting force
[N]
w
angle of incline
[1/s]
u
coefficient of friction
F
additional driving power
[N]
t
deceleration time
[s]
n
number of strokes per hour
[1/h]
B
angle
[°]
For all samples valid: braking deceleration time (s)
f = 2,6xs : VD
Attentione
retarding (m/s)
a = 0,6xVD2 :s
For individual matter in case of damp environment we beg to
contact our technical department: 07844/9138-0
Formulas/Calculation examples
Example:
W1 = 0,5 x m x v2
W1 = 0,5 x 200 x 2,52
625,0Nm
m=200kg
W2 = 0
W2 = 0
0,0Nm
v=2,5m/s
W3 = W1 + W2
W3 = 625 + 0
625,0Nm
n=120 1/h
W4 = W3 x n
W4 = 625 x 120
75.000Nm
s=0,025m
VD = V
2,5m/s
me = m
200,0kg
selection with W3, W4 und vD
M45 x 1.5S
( W3 = 650Nm, W4
= 150 000Nm/h, v = 1,4 - 3,5m/s )
Example:
W1 = 0,5 x m x v2
W1 = 0,5 x 30 x 1,92
54,2Nm
m=30kg
W2 = F x s
W2 = 300 x 0,025
7,5Nm
v=1,9m/s
W3 = W1 + W2
W3 = 54,15 + 7,5
61,7Nm
n=800 1/h
W4 = W3 x n
W4 = 61,65 x 800
49.320Nm
s=0,025m
1,9m/s
F=300N
me = 2 x W3 : vD2
me = 2 x 61,65 : 1,92
34,2kg
selection with W3, W4 und vD
M20 x 1.5S
( W3 = 70Nm, W4 =
63 000Nm/h, v = 1,8 - 4,5m/s )
Example:
W1 = 0,25 x m x v2
W1 = 0,25 x 650 x 0,82
234,0Nm
m=650kg
= 0,5 x J x w2
v=1,2m/s
W2 = M x s : R
W2 = 650 x 0,02 : 0,9
14,4Nm
n=90 1/h
W3 = W1 + W2
W3 = 234 + 14,44
248,4Nm
s=0,02m
W4 = W3 x n
W4 = 248,44 x 90
22.360Nm
R=0,9m
vD = v x R : L
vD=1,2 x 0,9 : 1,35
0,8m/s
M=1200Nm
= w x R
L=1,35m
me = 2 x W3 : vD2
me = 2 x 248,44 : 0,82
776,4kg
selection with W3 ,W4 und vD
M33 x 1.5H
( W3 = 320Nm, W4
= 120 000Nm/h, v = 0,2 - 0,8m/s )
Example:
W1 = m x v2 x 0,127
W1 = 320 x 1,82 x 0,17
489,6Nm
m=320kg
= 0,5 x J x w2
v=3m/s
W2 = F x r x s : R
W2 = 6000 x 0,7 x 0,025 : 0,9
116,7Nm
n=220 1/h
= M x s : R
s=0,025m
W3 = W1 + W2
W3 = 489,6 + 116,67
606,3Nm
R=0,9m
W4 = W3 x n
W4 = 606,27 x 220
133.379Nm
M=3200Nm
vD = v x R : L
vD =3 x 0,9 : 1,5
L=1,5m
= w x R
1,8m/s
F=6000N
me = 2 x W3 : vD2
me = 2 x 606,27 : 1,82
374,2kg
r=0,7m
selection with W3 ,W4 und vD
M45 x 1.5S
( W3 = 650Nm, W4
= 150 000Nm/h, v = 1,4 - 3,5m/s )
Example:
W1 = m x v2 x 0,127
W1 = 0,5 x 41 x 22
82,0Nm
J=41 kgm2
= 0,5 x J x w2
w=2 1/s
W2 = F x r x s : R
W2 = 400 x 0,025 : 0,9
11,1Nm
n=900 1/h
= M x s : R
s=0,025m
W3 = W1 + W2
W3 = 82 + 11,11
93,1Nm
R=0,9m
W4 = W3 x n
W4 = 93,11 x 900
83.800Nm
M=400Nm
vD = v x R : L
vD =2 x 0,9
L=1,8m
= w x R
1,8m/s
me = 2 x W3 : vD2
me = 2 x 93,11 : 1,82
57,5kg
selection with W3, W4 und vD
M25 x 1.5S
( W3 = 210Nm, W4
= 95 000Nm/h, v = 1,4 - 4,0m/s )
Example:
W1 = m x v2 x 0,5
W1 = 0,5 x 12 x 1,52
13,5Nm
m=12kg
= 0,5 x J x w2
v=1,5m/s
W2 = M x s : R
W2 = 60 x 0,02 : 0,6
2,0Nm
n=1600 1/h
W3 = W1 + W2
W3 = 13,5 + 2
15,5Nm
s=0,02m
W4 = W3 x n
W4 = 15,5 x 1600
24.800Nm
R=0,6m
vD = v x R : L
vD=1,5 x 0,6 : 0,9
M=60Nm
=w x R
1,0m/s
L=0,9m
me = 2 x W3 : vD2
me = 2 x 15,5 : 12
31,0kg
6. Mass without driving power
s
_JTT
m
7. Mass with driving power
F
1. Free falling Mass
s
Example:
W1 = m x g x h
W1 = 8 x 9,81 x 0,3
23,5Nm
m=8kg
W2 = m x g x s
W2 = 8 x 9,81 x 0,02
1,6Nm
h=0,3m
W3 = W1 + W2
W3 = 23,544 + 1,5696
25,1Nm
n=120 1/h
W4 = W3 x n
W4 = 25,1136 x 120
3014Nm
s=0,02m
vD = \2 x g x h
vD = \2 x 9,81 x 0,3
2,4m/s
me = 2 x W3 : vD2
me = 2 x 25,1136 : 2,43 2
8,5kg
selection with W3, W4 und VD
( W3 = 31Nm, W4 = 50 000Nm/h, vmax = 2,0 - 5,0m/s )
M14 x 1.5S
2. Lowered mass
without driving power
8. Rotating table with driving moment horizontal and vertical
H
Example:
W1 = 0,5 x m x v2
W1 = 0,5 x 400 x 12
200,0Nm
m=400kg
W2 = m x g x s
W2 = 400 x 9,81 x 0,02
78,5Nm
v=1m/s
W3 = W1 + W2
W3 = 200 + 78,48
278,5Nm
n=30 1/h
W4 = W3 x n
W4 = 278,48 x 30
8354Nm
s=0,02m
1,0m/s
me = 2 x W3 : vD2
me = 2 x 278,48 : 12
557,0kg
selection with W3 ,W4 und vD
M33 x 1.5M
( W3 = 320Nm, W4 =
120 000Nm/h, vmax = 0,6 - 2,0m/s )
V
m
K
s
3. Mass on driving rolls
9. Swivelling mass with driving power
W1 = 0,5 x m x v2 W2 = m x u x g x s W3 = W1 + W2
W4 = W3 x n
me = 2 x W3 : vD2
W1 = 0,5 x 190 x 1,82
W2 = 190 x 0,2 x 9,81 x 0,025
W3 = 307,8 + 9,3195
W4 = 317,1195 x 170
me = 2 x 317,1195 : 1,82
Example: m=190kg v=1,8m/s
n=170 1/h s=0,025m
[J=0,2
307,8Nm
9,3Nm
317,1Nm
53.910Nm
1,8m/s
195,8kg
M33 x 1.5M
selection with W3 ,W4 und vD
( W3 = 320Nm, W4 = 120 000Nm/h, vmax = 0,6 - 2,0m/s )
4. Mass with motor driving
10. Swivelling mass with driving power
Example:
W1 = 0,5 x m x v2
W1 = 0,5 x 320 x 1,32
270,4Nm
m=320kg
W2 = 1000 x P x HM x s : v
W2 = 1000 x 4 x 2,5 x 0,025 : 1,3
192,3Nm
v=1,3m/s
W3 = W1 + W2
W3 = 270,4 + 192,31
462,7Nm
n=80 1/h
W4 = W3 x n
W4 = 462,71 x 80
37.017Nm
s=0,025m
1,3m/s
P=4 kW
me = 2 x W3 : vD2
me = 2 x 462,71 : 1,32
547,6kg
HM= 2,5
selection with W3, W4 und vD
M45 x 1.5M
( W3 = 650Nm, W4 = 150 000Nm/h, vmax = 0,6 - 1,6m/s )
5. Mass on inclined plane
11. Swivelling mass with driving moment
M
Example:
W1 = m x g x h
W1 = 2 x 9,81 x 0,3
5,9Nm
m=2 kg
W2 = m x g x s x sin ß
W2 = 2 x 9,81 x 0,08 x sin 20
0,5Nm
h=0,3 m
W3 = W1 + W2
W3 = 5,89 + 0,54
6,4Nm
n=120 1/h
W4 = W3 x n
W4 = 6,42 x 120
771Nm
s=0,08m
vD = V2 x g x h
vD = V2 x 9,81 x 0,3
2,4m/s
ß=20 °
me = 2 x W3 : vD2
me = 2 x 6,42 : 2,432
2,2kg
selection with W3, W4 und vD
( W3 = 10Nm, W4 = 8 000Nm/h, v = 2,0 - 5,0m/s )
M10x 1S
selection with W3, W4 und vD
( W3 = 16Nm, W4 = 30 000Nm/h, v = 0,2 - 1,4m/s )
M12 x 1H
ZIMMER
TEGHHISGHE WERKSTÄTTEN
ZIMMER
TECHNISCHE WEFKSTATTEM
© +49.7844.9138-0
www.zimmer-gmbh.com
I
©+49.7844.9138-0 www.zimmer-gmbh.com
27
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