AC SERVO DRIVES - YASKAWA - #351

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i Selecting Servomotor Capacity and Regenerative Capacity
Servomotor Capacity Selection Examples
Use the AC servo drive capacity selection program SigmaJunmaSize+ to select servomotor capacity. The program can be downloaded for free from our web site (http://www.e-mechatronics.com/).
• Selection Example for Speed Control
• Gear + coupling moment of inertia
: Jg = 0.40X10-4 kg-m2
• Feeding times: n = 40 times/min
• Feeding distance: £ = 0.275 m
• Feeding time: tm = 1.2 s max.
Load speed: Vl = 15 m/min • Linear motion section mass: m = 250 kg Ball screw length: £fi = 1.0 m Ball screw diameter: ofe = 0.02 m Ball screw lead: Pb = 0.01 m
Mechanical Specifications
Servomotor
Linear motion
\
Ball screw
Ball screw material density: p =7.87x103 kg/m3 • Friction coefficient: ^ = 0.2
Gear ratio: 1/2 (R = 2) ■ Mechanical efficiency: n = 0.9 (90%)
Gear
(1) Speed Diagram
.60 60 . c , ) t = 7T = 40 = 15 (s)
where ta = td
ta = tm - ?" = 1.2 - 60 X1°275 = 1.2 - 1.1 = 0.1 (s)
V 15
tc = 1.2 - 0.1 x 2 = 1.0 (s)
15 Speed (m/min)
l)L
7T \ r
Time (s)
td
ta
tc
tm
(2) Rotation Speed
\)l _ 15
1500 (min1)
Load axis rotation speed m
Pb 0.01
• Motor shaft rotation speed Gear ratio 1/R = 1/2 (R=2)
Therefore, nu = nL- R = 1500 x 2 = 3000 (min-1)
(3) Load torque
9.8u-m-PB 9.8 x 0.2 x 250 x 0.01 \
Tl = 2n R-n =-2n x 2 x 0.9-= 043 (N'm)
(4) Load Moment of Inertia
0.01
1.58 x 104 (kg-m2)
• Linear motion section Jli = m
2n x 2
Ball screw
Coupling
Load moment of inertia at motor shaft
0.31 x 10-4 (kg-m2)
Jb
— P -&B-dB4- = 7.87 x 1Q3 x 1.0 x (0.Q2)4- —
22
32 - r2 32
Jg = 0.40 x 104 (kg-m2)
Jl = Jli + Jb + Jg = (1.58 + 0.31 + 0.40) x 104 = 2.29 x 104 (kg-m2)
(5) Load Moving Power
135(W)
Po :
2nnu -Tl 2n X 3000 X 0.43
60
60

pageCatalog pdf di En 2012-06-22-01