fig, it is first necessaryto calculate the basic rating life for the
individual time periods using mean
values of the load and the sliding vel-
ocity for the individual time periods.
When this has been done, the total
basic rating life can be calculatedusing the following equation >
1
Product information >
2
Recommendations >
3
Product data Page ................4 fig the individual basic rating lifecan be calculated using the constant
values of p and v. However, when the
load and sliding velocity are not con-
stant (b) in Basic rating life Page ..............57 Calculation examples >
Variable load and sliding velocity
1G >
h = –––––––––––––––––––––––t >
Calculation examples
If, during operation, the load and/or thesliding velocity change it is first neces-
sary to calculate individual rating lives
for the periods of constant load and
sliding velocity, before the basic rating
lifecan be calculated. If the load and
sliding velocity occur as shown by (a)
in –––––+–––––+––––– +…T G >
1 t >
2 t >
3 The calculation examples shown in the following serve to illustrate themethods used to calculate the requis-ite bearing size or the basic rating life
for spherical
plain bearings manufacturer and
rod ends.Using the SKF Interactive Engin-eering Catalogue which incorporates
programs to do these and many other
calculations, results will be obtained
quickly and accurately. Additionally, the
programs can be run any number of
times to enable the best possible solu-
tion to be obtained.The SKF Interactive EngineeringCatalogue is available on CD-ROM or
online at www.skf.com. >
h1 T G >
h2 T G >
h3 whereG >
h =total basic rating life, operat-ing hours t >
12 1 , t >
2 …=time during which p >
1 and v >
1 , p >
2 and v >
2 etc. pertain, hT=total duration of one cycle (= t >
12 1 + t >
2 + t >
3 + …), h G >
h1 …=individual values of rating lifefor conditions p >
1 and v >
1 , p >
2 and v >
2 etc., operating hours >
Alternating load and variable sliding velocity Fig 12 vpvp p 2 vpvp 1 v v 2 v 2 31
1 p 1 p 3 p 2 4 v 3 v 4
1
1 p 3 t t 2 t 3 tt 4 t t 2 tt 3 a T b T 30 >