| The total service factor for helical-worm gear units is calculated as follows: Example The gearmotor with the service factor fB = 1.51 in the previous example is to be a helical- Ambient temperature $ = 40°C — = 1.38 (read off at load classification II) Time under load = 40 min/h — cdf = 66.67% — fB2 = 0.95 The total service factor is fBges = 1.51 • 1.38 • 0.95 = 1.98 According to the selection tables, the selected helical-worm gearmotor must have an SEW fB service factor of 1.98 or greater. |