Recoil Technical catalogue - RECOIL - #39

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Text version of the page
Assembly Design
Determine the length of insert based on shear strength of parent material
Step Four,
Nominal Diameter Pitch
Pitch Diameter (min)
16.0 mm (selected bolt) 2.0 mm 17.299mm (refer taped hole data)
Tensile Strength of Bolt
Nominal Diameter TPI
Pitch Diameter (min)
0.500" (selected bolt)
13
0.550"
(refer taped hole data)
Tensile Strength of Bolt
L = -
L =-
Shear Circumference Strength of Hole x Arbitrary Constant
Shear Circumference Strength of Hole x Arbitrary Constant
= Required length of fitted insert
Arbitrary Constant = 0.5
(0.5 Based on shearing of the parent material occurring along the pitch diameter of the tapped hole)
= Required length of fitted insert
Arbitrary Constant = 0.5
(0.5 Based on shearing of the parent material occurring along the pitch diameter of the tapped hole)
L = 181,000 X (0.4072 X K/4)
25,000 X 0.550 K X 0.5 L = 1.09"
Conclusion:
For this application a 1/2" diameter bolt has been selected. Insert engagement of 1.09" was calculated. The suitable diameter of the insert can be determined by dividing the length of the insert by the diameter of the bolt.
For example:
L/dia = 1.09"/0.5"
= 2.2 select next highest size Therefore use a 2.5D insert
L
1034 X (13.7972 X K/4)
283 X 17.299 K X 0.5
L = 20.1mm
Conclusion:
For this application a 16mm diameter bolt has been selected.Insert engagement of 20.1mm was calculated. The suitable diameter of the insert can be determined by dividing the length of the insert by the diameter of the
bolt.
For example:
L/dia = 20.1mm/16mm
= 1.26 select next highest size Therefore use a 1.5D insert
Calculated Load
of Assembly (pounds)
Tensile
Strength - Bolt
Tensile
Strength - Bolt
Calculated Load of Assembly (kN)
200
50,000
1250 Mpa bolt
40,000
160
1034 Mpa
bolt
700 Mpa
bolt
220,000psi
bolt
30,000
120
180,000psi bolt
20,000
80
120,000psi bolt
10,000
40
60,000psi bolt
5,000
15,000 25,000 35,000 45,000
Shear Strength - Parent Material (psi)
20
100 180 260
Shear Strength - Parent Material (Mpa)
340
The shaded area in the graph indicates the region in which bolt failure will occur.
The shaded area in the graph indicates the region in which bolt failure will occur.
Note: Inserts are available in standard lengths which are multiples of the diameter. For example an insert with a length of 1.5D will measure one and a half times as long as the diameter when installed.
Note: The example above is an indication only. Professional engineering advice must be sought when exact design calculations are required.
1.5D = 1 1/2 times length of insert
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E b
37

pageCatalog pdf di En 2012-06-22-01