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| | | LINEAR | | |
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| | | Drylin® T Linear Bearings with High Performance Polymers | | |
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| | | | | | | | | | | Part Number | Sy, ay (mm) | Sz, az (mm) | | | | TW01-15 | 2Wx - 11.5mm | 2Wx | | | | TW01-20 | 2Wx - 15.0mm | 2Wx | | | | TW01-25 | 2Wx - 19.0mm | 2Wx | | | | TW01-30 | 2Wx - 21.5mm | 2Wx | | | | | | | | | | |
| | | One Rail and Two Carriages Step 2: maximum allowable distances between the acting forces Horizontal Mounting | | |
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| | | Step 3: calculate required driving force Fs |j Wx (Zm+2Sz) Fa = - Zm (Wx-2az|j) Step 4: maximum bearing load in y direction | | |
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| | | Sxk Sz 2|j (ay+Yo) (Zm+2Sz) — + — + - |_Wx Zm Zm (Wx-2az|j) | | |
| | | Fs | | |
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| | | Fy max = | | |
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| | | Sxk=Wx - Sx (if Sx <0.5Wx) Sxk=Sx (if Wx >Sx >0.5Wx) maximum bearing load in z direction | | |
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| | | Fs m az (Zm+2Sz) | | |
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| | | Fz max = | | |
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| | | Zm (Wx-2az|j) Vertical Mounting Step 3: calculate required driving force Fs |J Wx [ZM+2(Sy+Yo)] Fa = - Zm [Wx-2|j (ay+Yo)] Step 4: maximum bearing load in y direction | | |
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| | | Sxk Sy+Yo |j az [ZM+2(Sy+Yo)] 1--+ - + - | | |
| | | Fy max = Fs | | |
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| | | Zm [Wx-2|j (ay+Yo)jj | | |
| | | Wx 2Zm | | |
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| | | Sxk=Wx - Sx (if Sx <0.5Wx) Sxk=Sx (if Wx >Sx >0.5Wx) | | |
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| | | maximum bearing load in z direction | | |
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| | | Sy m (ay+Yo) [ZM+2(Sy+Yo)J | | |
| | | FS | | |
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| | | Fz max = | | |
| | | + | | |
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| | | 2 I_Zm Zm [Wx-2m (ay+Yo)] ondrives | | |
| | | H sales@ondrives.com B3B www^.ondrives.com | | |
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| | +44 (0)1246 455500 +44 (0)1246 455522 | | |
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