|
catalogue search
|
You may also be interested in
Wire rope isolator, Rotary damper, Vibration damper, Polyurethane bumper, Bumper
Text version of the page
Shock Absorber Sizing Examples Typical Shock Absorber ApplicationsOverviewEXAMPLE 3: Vertical Moving Load withPropelling Force Upward STEP 2: Calculate kinetic energy STEP 1: Application Data E STEP 3: Calculate work energy STEP 5: Calculate totalenergy per hour E (W) Weight = 3,400 lbs. (V) Velocity = 80 in./sec. (d) 2 Cylinders bore dia. = 6 in. (P) Operating pressure = 70 psi (C) Cycles/Hr = 200 FD =2 x [ .7854 x d 2 x P] – W F D =2 x [ .7854 x 6 2 x 70] – 3,400 F T C=E T x C E D =558 lbs. E T C=30,977 x 200 E W =F D X S E T C=6,195,400 in-lbs./hr Model OEM 3.0M x 5 is adequate. W =558 x 5 E W =2,790 in-lbs. 2 2 STEP 4: Calculate total energy per cycle E K = W W W 772772 x V = 3,400x 80 E K =28,187 in-lbs.Assume Model OEM 3.0M x 5 isadequate (Page 31). T =E K + E W E T =28,187 + 2,790 E T =30,977 in-lbs./c Shock Absorber Sizing Examples EXAMPLE 4: Vertical Moving Load with Propelling Force from Motor STEP 2: Calculate kinetic energy Assume Model OEMXT 2.0M x 2 isadequate (Page 29). E (W) Weight =200 lbs. (V) Velocity =60 in./sec. (Hp) Motor horsepower = 1.5 Hp (C) Cycles/Hr = 100 E W =F D X SE W =F D x SE W =295 x 2E W =695 x 2E W =590 in-lbs. W =1,390 in-lbs. STEP 4: Calculate total energy per cycle STEP 4: Calculate total energy per cycle K =Wx V 2 E T =E K + E W 772772 = 200x 60 2 E T =E K + E W E T =933 + 590E E T =933 + 1,390E E K =933 in-lbs. T =1,523 in-lbs./c T =2,323 in-lbs./c STEP 5: Calculate total energy per hour CASEA: UP STEP 5: Calculate total energy per hour STEP 3: Calculate work energy E T C=E T x CE E 19,800 x Hp– WVF T C = E T x CE F D = T C=1,523 x 100E T C = 2,323 x 100E C =152,300 in-lbs./hrModel OEM 1.25 x 2 is adequate. 19,800 x 1.5– 20060F T T C = 232,300 in-lbs./hrModel OEMXT 2.0M x 2 is adequate. D = D =295 lbs. Assume Model OEM 1.25 x 2 is adequate (Page 24).E CASE B: DOWN STEP 3: Calculate work energy F D = 19,800 x Hp+ WVF D = 19,800 x 1.5+ 20060F D =695 lbs. (e.g., Load Moving Force Up) EXAMPLE 5: Horizontal Moving Load STEP 1: Application Data E STEP 1: Application Data STEP 3: Calculate work energy: N/A (W) Weight=1,950 lbs. (V) Velocity=60 in./sec. (C) Cycles/Hr=200 STEP 2: Calculate kinetic energy STEP 4: Calculate total energy per cycle E T =E K = 9,093 in-lbs./c STEP 5: Calculate total energy per hour K = W Wx V 2 E T C=E T x C E 772 T C=9,093 x 200 E E K =1950x 60 2 T C=1,818,600 in-lbs./hr Model OEMXT 2.0M x 2 is adequate. 772 E K =9,093 in-lbs.Assume Model OEMXT 2.0M x 2 isadequate (Page 29). 7www.enidine.com Email: industrialsales@enidine.comTel.: 1-800-852-8508 ext. 111Fax: 1-716-662-0406 |