Shock Absorber Catalog (I & M) - ITT Enidine Inc. - #10

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Shock Absorber Sizing Examples Typical Shock Absorber Applications

Overview

EXAMPLE 3: Vertical Moving Load withPropelling Force Upward STEP 2: Calculate kinetic energy STEP 1: Application Data E STEP 3: Calculate work energy STEP 5: Calculate totalenergy per hour E (W) Weight = 3,400 lbs. (V) Velocity = 80 in./sec. (d) 2 Cylinders bore dia. = 6 in. (P) Operating pressure = 70 psi (C) Cycles/Hr = 200 F
D =2 x [ .7854 x d
2 x P] – W F
D =2 x [ .7854 x 6
2 x 70] – 3,400 F
T C=E
T x C E
D =558 lbs. E
T C=30,977 x 200 E
W =F
D X S E
T C=6,195,400 in-lbs./hr Model OEM 3.0M x 5 is adequate.
W =558 x 5 E
W =2,790 in-lbs.
2 2 STEP 4: Calculate total energy per cycle E
K = W W W 772772 x V = 3,400x 80 E
K =28,187 in-lbs.Assume Model OEM 3.0M x 5 isadequate (Page 31).
T =E
K + E
W E
T =28,187 + 2,790 E
T =30,977 in-lbs./c
Shock Absorber Sizing Examples EXAMPLE 4: Vertical Moving Load with Propelling Force from Motor STEP 2: Calculate kinetic energy Assume Model OEMXT 2.0M x 2 isadequate (Page 29). E (W) Weight =200 lbs. (V) Velocity =60 in./sec. (Hp) Motor horsepower = 1.5 Hp (C) Cycles/Hr = 100 E
W =F
D X SE
W =F
D x SE
W =295 x 2E
W =695 x 2E
W =590 in-lbs.
W =1,390 in-lbs. STEP 4: Calculate total energy per cycle STEP 4: Calculate total energy per cycle
K =Wx V
2 E
T =E
K + E
W 772772 = 200x 60
2 E
T =E
K + E
W E
T =933 + 590E E
T =933 + 1,390E E
K =933 in-lbs.
T =1,523 in-lbs./c
T =2,323 in-lbs./c STEP 5: Calculate total energy per hour CASEA: UP STEP 5: Calculate total energy per hour STEP 3: Calculate work energy E
T C=E
T x CE E 19,800 x Hp– WVF
T C = E
T x CE F
D =
T C=1,523 x 100E
T C = 2,323 x 100E C =152,300 in-lbs./hrModel OEM 1.25 x 2 is adequate. 19,800 x 1.5– 20060F
T T C = 232,300 in-lbs./hrModel OEMXT 2.0M x 2 is adequate.
D =
D =295 lbs. Assume Model OEM 1.25 x 2 is adequate (Page 24).E CASE B: DOWN STEP 3: Calculate work energy F
D = 19,800 x Hp+ WVF
D = 19,800 x 1.5+ 20060F
D =695 lbs.
(e.g., Load Moving Force Up) EXAMPLE 5: Horizontal Moving Load STEP 1: Application Data E STEP 1: Application Data STEP 3: Calculate work energy: N/A (W) Weight=1,950 lbs. (V) Velocity=60 in./sec. (C) Cycles/Hr=200 STEP 2: Calculate kinetic energy STEP 4: Calculate total energy per cycle E
T =E
K = 9,093 in-lbs./c STEP 5: Calculate total energy per hour
K = W Wx V
2 E
T C=E
T x C E 772
T C=9,093 x 200 E E
K =1950x 60
2 T C=1,818,600 in-lbs./hr Model OEMXT 2.0M x 2 is adequate. 772 E
K =9,093 in-lbs.Assume Model OEMXT 2.0M x 2 isadequate (Page 29).

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