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Shock Absorber Sizing Examples Typical Shock Absorber Applications

(d) Cylinder bore diamter = 6 in. (P) Cylinder pressure = 80 psi F

Overview

Shock Absorber Sizing Examples EXAMPLE 3: Horizontal Moving Load E STEP 1: Application Data (W) Weight=20,000 lbs. (V) Velocity=20 in./sec. (C) Cycles/Hr=4 STEP 2: Calculate kinetic energy
D = .7854 x d
2 x PF
D = .7854 x 6
2 x 80 psiF
D = 2,262 lbs.E
K = W Wx V
2 772
w = F
D x SE E
K =20,000 x 20
2 772
w = 2,262 x 2E E
w = 4,524 in-lbs.
K =10,364 in-lbs.Assume Model HD 1.5 x 2 isadequate (Page 13). STEP 3b: Calculate work energy: (Hp) Motor Horsepower = 5 Hp F
D = 19,800 x HpVF If there is no additional drive force proceed to step 4 and E
D = 19,800 x 520F
w = 0. If theapplication is driven by a cylinder, proceed to step 3a. If the application is driven by a motor proceed to step 3b. STEP 3a: Calculate work energy:
D = 4,950 in-lbs.E
w = F
D x SE
w = 4,950 x 2E
w = 9,900 in-lbs. STEP 4: Calculate total energy per cycleNote: Using Calculations from 3a E
T =E
K + E
w E
T =10,364 + 4,524E
T = 14,888 in-lbs. STEP 5: Calculate total energy per hour E
T C=E
T x C E
T C=14,888 x 4 E
T C=59,552 in-lbs./hr Model HD 1.5 x 2 is adequate.
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