Industrial shock absorber Sizing Examples Typical Shock Absorber Applications

Overview

Shock Absorber Sizing Examples EXAMPLE 18: STEP1: Application Data ω Ι ) Known Intertia = 885 in-lbs/sec. ) Angular Velocity = 2 rad/sec.(T) Torque = 2,750 in-lbs. ( STEP 2:Calculate kinetic energy STEP 5: Calculate total energy per hour: not applicable, C=1 E Vertical Rotation with Known Intertia Aided by Gravity (w/Torque) (W) Weight = 220.5 lbs. ( E
K =( Ι x ω
2 )/2E
2 K =(885 x 2 )/2E
T C = E
T x CE
K = 1,770 in-lbs.
T C = 1,780.4x 100E
2 T C = 178,040in-lbs/hr. (C/G) Center-of-Gravity = 12 in.( STEP 3: Calculate work energy θ ) Starting point fromtrue vertical = 120 F
D = [T – (W x C/G x Sin ( θ
θ – Ø)]/R
S STEP 6: Calculate impact velocity and confirm selection V = R (Ø) Angle of rotation at impact = 30° (R

Ëš

F
D =[2,750 – (220.5 x 12 x Sin (120 º –30 º )]/10F
D = 10.4 lbs.E
S x ω = 10 x 2 = 20 in./sec.Model OEM 1.15M x 1 is adequate(Page 24).
S ) Mounting radius = 10 in.(C) Cycles/Hr = 100
W = F
D x S = 10.4 x 1 = 10.4 in-lbs. STEP 4: Calculate total energy per cycle E
T = E
K + E
W = 1,770 + 10.4E
T = 1,780.4 in-lbs/cyc. E EXAMPLE 19: STEP1: Application Data ω ) Angular velocity = 2 rad./sec.(T) Torque = 2,750 in-lbs. (A) Length = 40 in. (R STEP 2:Calculate kinetic energy Vertical Roation Pinned at Center (w/Torque)STEP 4: Calculate total energy per cycle (W) Weight = 220.5 lbs. ( K=.289 x (A
2 2 + B
2 )
0.5 K=.289 x (40
T = E
K + E
W = 153.8 + 275 E
2 + 2
2 )
0.5 = 11.6 in. I = (W/386) x K
T = 428.8 in-lbs./cycle I = (220.5/386) x 11.6
2 ) Mounting radius = 10 in.(B) Thickness = 2 in. (C) Cycles/Hr = 100
2 = 76.9 in-lb/sec
2 STEP 5: Calculate total energy per hour E
S E
K = ( Ι x ω )/2E
2 K = ( 76.9 x 2 )/2E
T C = E
T x CE
K = 153.8 in-lbs.Assume Model OEM 1.0 is adequate (Page 21).
T C = 428.8 x 100E
T C = 42,880 in-lbs./hr. STEP 6: Calculate impact velocity and confirm selection V = R STEP 3: Calculate work energy
S x ω = 10 x 2 = 20 in./sec.Model OEM 1.0 is adequate. F
D = T/R
S F
D =2,750/10F
D = 275 lbs.E
W = F
D x S = 275 x 1 = 275 in-lbs.
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