VERTICAL & INCLINED APPLICATION EXAMPLES

W= Moving Weight, lbsV= Impact Velocity, ft/secF
H = Energy per Hour, in.- lbs/hrW
E 2 = Effective Weight, lbsW
E = External Propelling Force, lbsF
K = Kinetic Energy, in.- lbsE
E V = Parameter for use with Size Selection Tables
P = Total Propelling Force, lbsL= Total Distance Moved by Weight, including stroke inchesS= Shock absorber Stroke, inchesC= Number of Cycles per Hour E
P = Propelling Force Energy, in.- lbsE A= Angle of Inclined Plane from Horizontal, deg
C = Energy per Cycle, in.- lbsE
*For impact velocities of less than 1 ft/sec consult EFDYNengineering depart ment

FORMULAS:EXAMPLES: WEIGHT IN VERTICAL FREE FALL

F
P = WE W= 5,000 lbs; L = 48 in.; C = 10/hr; S = 8 in.E
K = W•(L-S)E
C = 5,000•(48) = 240,000 in.-lbsE
P = W•SE
H = 10• (240,000) = 2,400,000 in.-lbs/hrW
C = E
K +E
P ,orE
C = W•L
E = 240,000/(48-8) = 6,000 lbsW E
2 H = C•E
C E V = 240,000/.187 = 1,283,400Select RCOS-3X8-BS-RC-99 W
E = E
C /(L-S) W
E V
2 = E
C /.187V= [(L-S)/.187]
1/2 ( not usually needed for sizing)

WEIGHT SLIDING FREELY DOWN INCLINE

F

P = W• Sin (A)E W= 25,000 lbs; A = 30 ; L = 120 in.; C = 5/hr; S = 12 in.F

K = FP•(L-S)E
P = 25,000•Sin(30 ) = 12,500 lbsE
P = F
P •SE
K = 12,500•(120-12) = 1,350,000 in.-lbsE
C = E
K +E
P ,orE
C = F
P • L
P = 12,500•(12) = 150,000 in.-lbsE E
H = C•E
C C = 12,500•(120) = 1,500,000 in.-lbsE W
E = W•L /(L-S)
H = 5• (1,500,000) = 7,500,000 in.-lbs/hrW W
E V
2 = E
C /.187V=
E = 25,000•(120)/(120-12) = 27,800 lbsW [(L-S)•Sin (A)/.187]
1/2 E V
2 = 1,500,000/.187 = 8.021,400Select RCOS-4X12-BS-RC-99, 2 Required ( not usually needed for sizing)
SIZING FORMULAS

DOWN INCLINE WITH PROPELLING FORCE

F

P = F
E +W•Sin(A) W= 6,000 lbs; F
E = 4,000 lbs; A = 45 ; V = 6 ft/sec; C = 20/hr; S = 12 in. V= must be specified F

P = 4,000 + 6,000•Sin(45 ) = 8,240 lbsE E
2 K = 0.187•W•V
2 K = 0.187•(6,000)•(6) = 40,390 in.-lbsE E
P = F
P •SE
P = 8,240•(6) = 49,450 in.-lbsE
C = E
K +E
P C = 40,390 + 49,450 = 89,840 in.-lbsE E
H = C•E
C H = 20• (89,840) = 1,797,000 in.-lbs/hrW W
2 E = E
C /(.187•V
2 )
E = 89,840/[(.187)•(6) ]= 13,345 lbsW W
2 E V
2 = E
C /.187
E V = 89,840/.187 = 480,400Select RCOS-2X6-BS-RD-99

UP INCLINE WITH PROPELLING FORCE

F

P = F
E -W•Sin(A) W= 800 lbs; F
E = 500 lbs; A = 15 ; V = 5 ft/sec; C = 200/hr; S = 3 in. V= must be specified F

P = 500 - 800•Sin(15 ) = 293 lbsE E
2 K = 0.187•W•V
2 K = 0.187•(800)•(5) = 3,740 in.-lbsE E
P = F
P •SE
P = 293•(3) = 879 in.-lbsE
C = E
K +E
P C = 3,740 + 879 = 4,619 in.-lbsE E
H = C•E
C H = 200• (4,619) = 923,800 in.-lbs/hrW W
2 E = E
C /(.187•V
2 )
E = 4,619/[(.187)•(5) ]= 988 lbsW W
2 E V
2 = E
C /.187
E V = 4,619/.187 = 24,700Select SAS - 3/4X3-BS-MH-99**If R-series model is selected, the model description shouldinclude -20 instead of -99 to indicate a rod-down orientation.

1.800.950.1172

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