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DESIGN EXAMPLE

Previously, we gave all the basic information to design acapacitor. Now we apply these formulations on an example.

VnDETERMINATION

(see page 4)

HOT SPOT TEMPERATURECALCULATION

(see page 4) millimeters (inches) millimeters (inches) C = 2000 µFDC voltage = 2800 VF = 33 Hz I θ
amb = 50°C with natural convection
rms = 233 A From tables of values: In accordance to data: S = 89dm2 (Found in the table)R = 0.87m Ω (page 21) V
S r = 1590 VV
w = 2800 + 1590/2 = 3595V Solution: The hot spot temperature is therefore: C
n = 2060µF (page 21)V θ
HS = 68.7°C
n = 3650 VV
r = 0.45 x 3650 = 1642 V max.L x W= 340 x 152 (13.386 x 5.984)H= 855 (33.661)

MTBF CALCULATION

(see page 5)

CALORIFIC VALUE

(see page 8) For a train application (4) in favorable conditions (1) in accordance to IEC 61071 (2)Vw = 0.985 Vn (105,000 h of expected lifetime) L = 340 (13.386)W = 152 (5.984)H = 855 (33.661) N = 2 θ
HS = 68.7°C λ = λ
B x2x4x1 λ = 49.3x10
-9 failures/hour

MTBF = 20.3 x 10

6

hours CV#1827.5MJ

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